Pythagorean Theorem Calculator › Legs 6 and 11
Hypotenuse of 6 and 11
Hypotenuse = √157 ≈ 12.529964
For a right triangle with legs 6 and 11, the hypotenuse c satisfies a² + b² = c²:
6² + 11² = 36 + 121 = 157, so c = √157 ≈ 12.529964 (√157).
Other triangles with leg 6
6 & 1 · 6 & 2 · 6 & 3 · 6 & 4 · 6 & 5 · 6 & 6 · 6 & 7 · 6 & 8 · 6 & 9 · 6 & 10 · 6 & 12
Frequently asked questions
What is the hypotenuse of a triangle with legs 6 and 11?
It is √157 ≈ 12.529964 (or √157 in simplified radical form). Using a² + b² = c²: 6² + 11² = 157.
Is 6, 11, … a Pythagorean triple?
No. The hypotenuse √157 is not a whole number, so 6 and 11 do not form a Pythagorean triple with an integer hypotenuse.