Pythagorean Theorem Calculator › Legs 2 and 11
Hypotenuse of 2 and 11
Hypotenuse = √125 ≈ 11.18034
For a right triangle with legs 2 and 11, the hypotenuse c satisfies a² + b² = c²:
2² + 11² = 4 + 121 = 125, so c = √125 ≈ 11.18034 (5√5).
Other triangles with leg 2
2 & 1 · 2 & 2 · 2 & 3 · 2 & 4 · 2 & 5 · 2 & 6 · 2 & 7 · 2 & 8 · 2 & 9 · 2 & 10 · 2 & 12
Frequently asked questions
What is the hypotenuse of a triangle with legs 2 and 11?
It is √125 ≈ 11.18034 (or 5√5 in simplified radical form). Using a² + b² = c²: 2² + 11² = 125.
Is 2, 11, … a Pythagorean triple?
No. The hypotenuse √125 is not a whole number, so 2 and 11 do not form a Pythagorean triple with an integer hypotenuse.