Pythagorean Theorem Calculator › Legs 2 and 5
Hypotenuse of 2 and 5
Hypotenuse = √29 ≈ 5.385165
For a right triangle with legs 2 and 5, the hypotenuse c satisfies a² + b² = c²:
2² + 5² = 4 + 25 = 29, so c = √29 ≈ 5.385165 (√29).
Other triangles with leg 2
2 & 1 · 2 & 2 · 2 & 3 · 2 & 4 · 2 & 6 · 2 & 7 · 2 & 8 · 2 & 9 · 2 & 10 · 2 & 11 · 2 & 12
Frequently asked questions
What is the hypotenuse of a triangle with legs 2 and 5?
It is √29 ≈ 5.385165 (or √29 in simplified radical form). Using a² + b² = c²: 2² + 5² = 29.
Is 2, 5, … a Pythagorean triple?
No. The hypotenuse √29 is not a whole number, so 2 and 5 do not form a Pythagorean triple with an integer hypotenuse.